x^2+14x+20=0

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Solution for x^2+14x+20=0 equation:


Simplifying
x2 + 14x + 20 = 0

Reorder the terms:
20 + 14x + x2 = 0

Solving
20 + 14x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-20' to each side of the equation.
20 + 14x + -20 + x2 = 0 + -20

Reorder the terms:
20 + -20 + 14x + x2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + 14x + x2 = 0 + -20
14x + x2 = 0 + -20

Combine like terms: 0 + -20 = -20
14x + x2 = -20

The x term is 14x.  Take half its coefficient (7).
Square it (49) and add it to both sides.

Add '49' to each side of the equation.
14x + 49 + x2 = -20 + 49

Reorder the terms:
49 + 14x + x2 = -20 + 49

Combine like terms: -20 + 49 = 29
49 + 14x + x2 = 29

Factor a perfect square on the left side:
(x + 7)(x + 7) = 29

Calculate the square root of the right side: 5.385164807

Break this problem into two subproblems by setting 
(x + 7) equal to 5.385164807 and -5.385164807.

Subproblem 1

x + 7 = 5.385164807 Simplifying x + 7 = 5.385164807 Reorder the terms: 7 + x = 5.385164807 Solving 7 + x = 5.385164807 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + x = 5.385164807 + -7 Combine like terms: 7 + -7 = 0 0 + x = 5.385164807 + -7 x = 5.385164807 + -7 Combine like terms: 5.385164807 + -7 = -1.614835193 x = -1.614835193 Simplifying x = -1.614835193

Subproblem 2

x + 7 = -5.385164807 Simplifying x + 7 = -5.385164807 Reorder the terms: 7 + x = -5.385164807 Solving 7 + x = -5.385164807 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + x = -5.385164807 + -7 Combine like terms: 7 + -7 = 0 0 + x = -5.385164807 + -7 x = -5.385164807 + -7 Combine like terms: -5.385164807 + -7 = -12.385164807 x = -12.385164807 Simplifying x = -12.385164807

Solution

The solution to the problem is based on the solutions from the subproblems. x = {-1.614835193, -12.385164807}

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